One of the by-products formed during the recovery of $\mathrm{NH}_{3}$ from solvay process is:

(C) $\mathrm{Ca}(\mathrm{OH})_{2}$

(D) $\mathrm{NH}_{4} \mathrm{Cl}$

JEE Main · 2021 · 17 Mar 2021 · Shift 2 · s-Block Elements

One of the by-products formed during the recovery of

NH_{3}

from solvay process is:

(A) $NaHCO_{3}$
(B) $CaCl_{2}$ ✓ Correct
(C) $Ca (OH)_{2}$
(D) $NH_{4} Cl$

Answer: (B)

Solution

In the Solvay process the ammonia ends up locked as ammonium chloride in the mother liquor, and it is regenerated by heating that liquor with slaked lime:

2 N H_{4} Cl + Ca (OH)_{2} \to CaC l_{2} + 2 N H_{3} + 2 H_{2} O

The ammonia is returned to the ammoniation tower, while the calcium of the lime stays behind in solution paired with the chloride that came in with the brine. The by-product of this recovery step is

CaC l_{2}

JEE Main · 2021 · 17 Mar 2021 · Shift 2 · Single correct option

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JEE Main · 2021 · 17 Mar 2021 · Shift 2 · s-Block Elements

Solution

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