JEE Main · 2021 · 16 Mar 2021 · Shift 1 · Mathematical Reasoning *

A conditional is true whenever its antecedent is false, so $(p\wedge q)\to (p\to q)$ is true whenever $p\wedge q$ is false; and when $p\wedge q$ is true, both $p$ and $q$ are true, so $p\to q$ is true and the conditional is true again. It is therefore true for every assignment of truth values.
Of the others, $(p\wedge q)\vee (p\to q)$ is false at $p$ true and $q$ false, while $(p\wedge q)\wedge (p\to q)$ and $(p\wedge q)\vee (p\vee q)$ are both false at $p$ false and $q$ false.
The tautology is $(p\wedge q)\to (p\to q)$.