In the figure given, the electric current flowing through the 5 kΩ resistor is ' x ' mA . The value of x to the nearest integer is ____
Answer: 3
Solution
The three 3kΩ resistors are joined across the same pair of points, so together they amount to 33=1kΩ. That combination sits in series with the 5kΩ resistor and with the 1kΩ internal resistance of the cell, giving
R=5+1+1=7kΩ
The 5kΩ resistor lies in the single branch that carries the whole current, so
I=7×10321=3×10−3A
The current through it is 3 mA, so x=3.
JEE Main · 2021 · 16 Mar 2021 · Shift 1 · Integer answer