COMPASSLearning
RegisterLogin

JEE Main · 2021 · 27 Jul 2021 · Shift 2 · Atomic Structure

WhatsApp Email
If the Thompson model of the atom was correct, then the result of Rutherford's gold foil experiment would have been:
  1. (A)All -particles get bounced back by .
  2. (B) - particles are deflected over a wide range of angles.
  3. (C)All of -particles pass through the gold foil without decrease in speed.
  4. (D) - particles pass through the gold foil deflected by small angles and with reduced speed.✓ Correct

Answer: (D)

Solution

In Thomson's model the positive charge is smeared uniformly through the whole volume of the atom, so an -particle crossing the foil meets only a weak, diffuse field and never a concentrated centre of charge. Such a field can bend the path through a small angle and take away a little kinetic energy, but it cannot supply the large force needed to turn the particle through a wide angle. The expected result is that the -particles pass through the gold foil deflected by small angles and with reduced speed.

JEE Main · 2021 · 27 Jul 2021 · Shift 2 · Single correct option

Practise more: all JEE Main PYQs on Atomic Structure →

More JEE Main questions on Atomic Structure

  1. Given below are two statements:

    Statement I: When an electric discharge is passed through gaseous hydrogen, the hydrogen molecules dissociate and the energetically excited hydrogen atoms produce electromagnetic radiation of discrete frequencies.

    Statement II: The frequency of s …
    JEE Main 2026View solution →
  2. The energy required by electrons, present in the first Bohr orbit of hydrogen atom to be excited to second Bohr orbit is ____ .

    Given : .
    JEE Main 2026View solution →
  3. Consider the following spectral lines for atomic hydrogen:
    A. First line of Paschen series
    B. Second line of Balmer series
    C. Third line of Paschen series
    D. Fourth line of Bracket series

    The correct arrangement of the above lines in ascending order of energy is:
    JEE Main 2026View solution →
  4. The energy of first (lowest) Balmer line of H atom is x J. The energy (in J) of second Balmer line of H atom is :
    JEE Main 2026View solution →
  5. Which of the following statements regarding the energy of the stationary state is true in the following one-electron system ?
    JEE Main 2026View solution →
  6. Given,
    (A)
    (B)

    The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) respectively are :
    JEE Main 2026View solution →