JEE Main · 2021 · 31 Aug 2021 · Shift 1 · Continuity and Differentiability

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The function is not differentiable at exactly:
  1. (A)three points
  2. (B)four points
  3. (C)two points✓ Correct
  4. (D)one point

Answer: (C)

Solution

The factor has simple zeros at and , where has corners. The exponent is a perfect square, so is smooth and is differentiable everywhere and never zero. The product therefore fails to be differentiable only at and , that is, at two points.

JEE Main · 2021 · 31 Aug 2021 · Shift 1 · Single correct option

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