The number of stereoisomers possible for $$[\mathrm{Co}(\mathrm{ox})_{2}(\mathrm{Br})(\mathrm{NH}_{3})]^{2-}$$ ____ [ox = oxalate]

JEE Main · 2021 · 26 Feb 2021 · Shift 2 · Coordination Compounds

The number of stereoisomers possible for

[Co (ox)_{2} (Br) (NH_{3})]^{2 -}

____
[ox = oxalate]

Answer: 3

Solution

The complex is octahedral. The two oxalate ions are bidentate and take up four coordination sites, leaving two sites for

B r^{-}

and

N H_{3}

, which can therefore be trans or cis to each other. In the trans form the two oxalate rings lie in one plane and the molecule has a plane of symmetry, so it is optically inactive. In the cis form the two oxalate rings are mutually perpendicular and the molecule has neither a plane nor a centre of symmetry, so it exists as a pair of non-superimposable mirror images. One trans isomer together with the two enantiomers of the cis isomer gives

3

stereoisomers.

JEE Main · 2021 · 26 Feb 2021 · Shift 2 · Integer answer

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