Compound(s) which will liberate carbon dioxide with sodium bicarbonate solution is/are:
A= (see structure)
B= (see structure)
C= (see structure)ABC
(A)A and B only
(B)B and C only✓ Correct
(C)B only
(D)C only
Answer: (B)
Solution
Carbon dioxide is released from sodium bicarbonate only by an acid stronger than carbonic acid, whose pKa is about 6.4. The first compound is 2,4,6-triaminophenol: three electron-releasing amino groups push charge into the ring and destabilise its phenoxide, so it is even weaker than ordinary phenol and far weaker than carbonic acid. The second is benzoic acid, pKa≈4.2, in which the carboxylate charge is shared equally by two oxygen atoms. The third is picric acid, 2,4,6-trinitrophenol, where three nitro groups delocalise the phenoxide charge onto their oxygen atoms and bring the pKa down to about 0.4. Benzoic acid and picric acid liberate carbon dioxide; the triaminophenol does not.
JEE Main · 2021 · 25 Feb 2021 · Shift 1 · Single correct option