Match List - I and List - II List - I (a) (see structure) (b) (see structure) (c) (see structure) (d) (see structure) List - II (i) $\mathrm{Br}_{2} / \mathrm{NaOH}$ (ii) $\mathrm{H}_{2} / \mathrm{Pd}-\mathrm{BaSO}_{4}$ (iii) $\mathrm{Zn}(\mathrm{Hg}) /$ Conc. HCl (iv) $\mathrm{Cl}_{2} / \operatorname{Red} \mathrm{P}, \mathrm{H}_{2} \mathrm{O}$ Choose the correct answer from the options given below:

(D) (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

(A) (a) - (iii), (b) - (i), (c) - (iv), (d) -(ii)

(B) (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)

(C) (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)

JEE Main · 2021 · 24 Feb 2021 · Shift 2 · Aldehydes Ketones and Carboxylic Acids

Match List - I and List - II

List - I
(a) (see structure)
(b) (see structure)
(c) (see structure)
(d) (see structure)

List - II
(i)

Br_{2} / NaOH

(ii)

H_{2} / Pd - BaSO_{4}

(iii)

Zn (Hg) /

Conc. HCl
(iv)

Cl_{2} / Red P, H_{2} O

Choose the correct answer from the options given below:

Answer: (D)

The correct matches are: (a) Acid chloride → Aldehyde using

H_{2} / Pd - BaSO_{4}

(Rosenmund reduction); (b) Carboxylic acid → α-halo acid using

Cl_{2} / Red P, H_{2} O

(HVZ reaction); (c) Carboxamide → Amine using

Br_{2} / NaOH

(Hofmann bromamide degradation); (d) Ketone → Alkane using

Zn (Hg) /

Conc. HCl (Clemmensen reduction). Therefore, (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii).

JEE Main · 2021 · 24 Feb 2021 · Shift 2 · Single correct option