Match List-I with List-II: List - I (a) Magnetic Induction (b) Magnetic Flux (c) Magnetic Permeability (d) Magnetization List - II (i) \(\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\) (ii) \(\mathrm{M}^{0} \mathrm{~L}^{-1} \mathrm{~A}\) (iii) \(M T^{-2} A^{-1}\) (iv) \(M L T^{-2} A^{-2}\) Choose the most appropriate answer from the options given below:

From , the magnetic induction has . Magnetic flux is , so . Permeability follows from , which gives . Magnetization is magnetic moment per unit volume, so . Magnetic induction goes with , magnetic flux with , magnetic permeability with and magnetization with .

JEE Main · 2021 · 26 Aug 2021 · Shift 2 · Units & Measurement

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Match List-I with List-II:

List - I
(a) Magnetic Induction
(b) Magnetic Flux
(c) Magnetic Permeability
(d) Magnetization

List - II
(i)

ML^{2} T^{- 2} A^{- 1}

(ii)

M^{0} L^{- 1} A

(iii)

M T^{- 2} A^{- 1}

(iv)

M L T^{- 2} A^{- 2}

Choose the most appropriate answer from the options given below:

Answer: A → III, B → I, C → IV, D → II

Solution

From

F = B I L

, the magnetic induction has

[B] = \frac{ML T ^{- 2}}{A L} = M T^{- 2} A^{- 1}

.
Magnetic flux is

ϕ = B A

, so

[ϕ] = M T^{- 2} A^{- 1} \cdot L^{2} = M L^{2} T^{- 2} A^{- 1}

.
Permeability follows from

B = \frac{μ _{0} I}{2 π r}

, which gives

[μ] = \frac{M T ^{- 2} A ^{- 1} \cdot L}{A} = ML T^{- 2} A^{- 2}

.
Magnetization is magnetic moment per unit volume, so

[M] = \frac{A L ^{2}}{L ^{3}} = M^{0} L^{- 1} A

.
Magnetic induction goes with

M T^{- 2} A^{- 1}

, magnetic flux with

M L^{2} T^{- 2} A^{- 1}

, magnetic permeability with

ML T^{- 2} A^{- 2}

and magnetization with

M^{0} L^{- 1} A

JEE Main · 2021 · 26 Aug 2021 · Shift 2 · Match the columns

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JEE Main · 2021 · 26 Aug 2021 · Shift 2 · Units & Measurement

Solution

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