JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Modern Physics

For photons, the de Broglie relation gives $\lambda =\frac{h}{p}$, where $h$ is Planck's constant and $p$ is momentum.

Statement I: If two photons have equal momenta $p$, then $\lambda =\frac{h}{p}$ is the same for both. Statement I is true.

Statement II: Energy of a photon is $E=h\nu =\frac{hc}{\lambda }$ and momentum is $p=\frac{h}{\lambda }$. If wavelength $\lambda$ decreases, both $E$ and $p$ increase (not decrease). Statement II is false.

The answer is (D): Statement I is true but Statement II is false.