JEE Main · 2022 · 25 Jun 2022 · Shift 2 · Heat & Thermodynamics

A copper block of mass 5.0 kg is heated to a temperature of

50 0^{\circ} C

and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper:

0.39 Jg^{- 1}^{\circ} C^{- 1}

and latent heat of fusion of water :

335 J g^{- 1}

]

(A)1.5 kg
(B)5.8 kg
(C)2.9 kg✓ Correct
(D)3.8 kg

Answer: (C)

Solution

Heat released by copper cooling from

50 0^{\circ} C

0^{\circ} C

Q = m c Δ T = 5000 \times 0.39 \times 500 = 975 \times 1 0^{3} J

. Heat absorbed by ice to melt mass m:

Q = m \times 335 \times 1 0^{3}

. Equating:

m = \frac{975 \times 1 0 ^{3}}{335 \times 1 0 ^{3}} \approx 2.91 kg

JEE Main · 2022 · 25 Jun 2022 · Shift 2 · Single correct option

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