Atoms of element X form hcp lattice and those of element Y occupy 2/3 of its tetrahedral voids. The percentage of element X in the lattice is ______ (Nearest integer)
Answer: 43
Solution
In an hcp lattice, the number of atoms X = 6 (per unit cell). The number of tetrahedral voids = 2 × 6 = 12. Element Y occupies 2/3 of tetrahedral voids, so Y atoms = (2/3) × 12 = 8. Total atoms = 6 + 8 = 14. Percentage of X = (6/14) × 100 = 42.86 ≈ 43%.
JEE Main · 2022 · 24 Jun 2022 · Shift 1 · Integer answer