Identify the correct statement for \(\mathrm{B}_{2} \mathrm{H}_{6}\) from those given below. (A) In \(\mathrm{B}_{2} \mathrm{H}_{6}\), all B-H bonds are equivalent. (B) In \(\mathrm{B}_{2} \mathrm{H}_{6}\) there are four 3-centre-2-electron bonds. (C) \(\mathrm{B}_{2} \mathrm{H}_{6}\) is a Lewis acid. (D) \(\mathrm{B}_{2} \mathrm{H}_{6}\) can be synthesized form both \(\mathrm{BF}_{3}\) and \(\mathrm{NaBH}_{4}\). (E) \(\mathrm{B}_{2} \mathrm{H}_{6}\) is a planar molecule. Choose the most appropriate answer from the options given below :

JEE Main · 2022 · 24 Jun 2022 · Shift 1 · Chemical Bonding and Molecular Structure

Identify the correct statement for

B_{2} H_{6}

from those given below.
(A) In

B_{2} H_{6}

, all B-H bonds are equivalent.
(B) In

B_{2} H_{6}

there are four 3-centre-2-electron bonds.
(C)

B_{2} H_{6}

is a Lewis acid.
(D)

B_{2} H_{6}

can be synthesized form both

BF_{3}

and

NaBH_{4}

.
(E)

B_{2} H_{6}

is a planar molecule.

Choose the most appropriate answer from the options given below :

(A)(A) and (E) only
(B)(B), (C) and (E) only
(C)(C) and (D) only✓ Correct
(D)(C) and (E) only

Answer: (C)

Solution

Statement (A) is incorrect:

B_{2} H_{6}

has terminal and bridging B-H bonds which are not equivalent. Statement (B) is incorrect: there are two 3-centre-2-electron bonds (the bridging B-H-B bonds), not four. Statement (C) is correct:

B_{2} H_{6}

is electron-deficient and acts as a Lewis acid. Statement (D) is correct:

B_{2} H_{6}

can be synthesized from

BF_{3}

(with

LiAlH_{4}

) and from

NaBH_{4}

(with

I_{2}

). Statement (E) is incorrect:

B_{2} H_{6}

is non-planar. Correct statements: (C) and (D). Answer: (C).

JEE Main · 2022 · 24 Jun 2022 · Shift 1 · Single correct option

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JEE Main · 2022 · 24 Jun 2022 · Shift 1 · Chemical Bonding and Molecular Structure

Solution

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