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JEE Main · 2022 · 27 Jun 2022 · Shift 1 · Chemical Bonding and Molecular Structure

Based upon VSEPR theory, match the shape (geometry) of the molecules in List-I with the molecules in List-II and select the most appropriate option

List-I (Shape):
(A) T-shaped
(B) Trigonal planar
(C) Square planar
(D) See-saw

List-II (Molecules):
(I)

XeF_{4}

(II)

SF_{4}

(III)

ClF_{3}

(IV)

BF_{3}

(A)(A) - I, (B) - (II), (C) - (III), (D) - (IV)
(B)(A) - (III), (B) - (IV), (C) - (I), (D) - (II)✓ Correct
(C)(A) - (III), (B) - (IV), (C) - (II), (D) - (I)
(D)(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

Answer: (B)

Solution

Using VSEPR theory:

$ClF_{3}$ has 5 electron pairs (3 bonding, 2 lone pairs) → T-shaped
$BF_{3}$ has 3 bonding pairs, no lone pairs → Trigonal planar
$XeF_{4}$ has 6 electron pairs (4 bonding, 2 lone pairs) → Square planar
$SF_{4}$ has 5 electron pairs (4 bonding, 1 lone pair) → See-saw

Therefore: (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

JEE Main · 2022 · 27 Jun 2022 · Shift 1 · Single correct option

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