Let the normal at the point P on the parabola y2=6x pass through the point (5,−8). If the tangent at P to the parabola intersects its directrix at the point Q, then the ordinate of the point Q is:
(A)-3
(B)−49✓ Correct
(C)−25
(D)-2
Answer: (B)
Solution
For the parabola y2=6x, we have 4a=6, so a=23. The equation of the normal at a point (at2,2at) is y=−tx+2at+at3. Since this passes through (5,−8), substituting gives −8=−5t+3t+23t3, which simplifies to t=−2. The point P is (6,−6). The tangent at P has equation x+2y+6=0. The directrix is x=−23. Substituting into the tangent equation: −23+2y+6=0, giving y=−49.
JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Single correct option