In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be ____ .
Answer: 5
Solution
Given: 20 MSD = 1 cm, so 1 MSD = cm.
10 VSD = 9 MSD, so 1 VSD = MSD = cm.
Vernier constant (VC) = 1 MSD − 1 VSD:
Therefore, the answer is 5.
10 VSD = 9 MSD, so 1 VSD = MSD = cm.
Vernier constant (VC) = 1 MSD − 1 VSD:
Therefore, the answer is 5.
JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Integer answer