JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Kinematics

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A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ____ m. (Use g = 10 m/s²).

Answer: 5

Solution

The ball is in free fall with acceleration

g = 10

m/s². We need to find the height where velocity magnitude equals

g

, i.e.,

v = 10

m/s. Using

v^{2} = u^{2} + 2 a s

with

u = 0

a = 10

m/s², and

v = 10

m/s:

100 = 0 + 2 (10) s

, giving

s = 5

m. This is the distance fallen. The height from ground is

10 - 5 = 5

JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Integer answer

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