JEE Main · 2022 · 27 Jun 2022 · Shift 2 · Practical and Analytical Chemistry

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0.25 g of an organic compound containing chlorine gave 0.40 g of silver chloride in Carius estimation. The percentage of chlorine present in the compound is ______. [in nearest integer]
(Given: Molar mass of Ag is

108 g mol^{- 1}

and that of Cl is

35.5 g mol^{- 1}

)

Answer: 40

Solution

In Carius estimation, all chlorine from the organic compound is converted to AgCl.

Molar mass of AgCl

= 108 + 35.5 = 143.5

g mol

^{- 1}

Mass of Cl in 0.40 g AgCl

= \frac{35.5}{143.5} \times 0.40

g

Percentage of Cl in the organic compound:

% Cl = \frac{mass of Cl}{mass of compound} \times 100 = \frac{35.5 \times 0.40}{143.5 \times 0.25} \times 100 = \frac{14.2}{35.875} \times 100 \approx 39.6%

Rounding to nearest integer:

40%

JEE Main · 2022 · 27 Jun 2022 · Shift 2 · Integer answer

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