JEE Main · 2022 · 26 Jul 2022 · Shift 1 · s-Block Elements

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Reaction of BeCl₂ with LiAlH₄ gives:
(A) AlCl₃
(B) BeH₂
(C) LiH
(D) LiCl
(E) BeAlH₄

Choose the correct answer from options given below:
  1. (A)(A), (D) and (E)
  2. (B)(A), (B) and (D)✓ Correct
  3. (C)(D) and (E)
  4. (D)(B), (C) and (D)

Answer: (B)

Solution

The reaction between BeCl₂ and LiAlH₄ is a metathesis reaction:



The products formed are:
  • BeH₂ (beryllium hydride)
  • LiCl (lithium chloride)
  • AlCl₃ (aluminum chloride)

Answer: (B) (A), (B) and (D).

JEE Main · 2022 · 26 Jul 2022 · Shift 1 · Single correct option

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