Given two statements below:
Statement I: In Cl₂ molecule the covalent radius is double of the atomic radius of chlorine.
Statement II: Radius of anionic species is always greater than their parent atomic radius.
Choose the most appropriate answer from options given below:
Statement I: In Cl₂ molecule the covalent radius is double of the atomic radius of chlorine.
Statement II: Radius of anionic species is always greater than their parent atomic radius.
Choose the most appropriate answer from options given below:
- (A)Both Statement I and Statement II are correct.
- (B)Both Statement I and Statement II are incorrect.
- (C)Statement I is correct but Statement II is incorrect.
- (D)Statement I is incorrect but Statement II is correct.✓ Correct
Answer: (D)
Solution
Statement I: In Cl₂ molecule, the covalent radius is defined as half of the internuclear distance (Cl-Cl bond length), not double the atomic radius. Hence Statement I is incorrect.
Statement II: When an atom gains an electron to form an anion, the effective nuclear charge per electron decreases, leading to increased electron-electron repulsion. This causes the electron cloud to expand, making the anionic radius larger than the parent atomic radius. Hence Statement II is correct.
Answer: (D) Statement I is incorrect but Statement II is correct.
Statement II: When an atom gains an electron to form an anion, the effective nuclear charge per electron decreases, leading to increased electron-electron repulsion. This causes the electron cloud to expand, making the anionic radius larger than the parent atomic radius. Hence Statement II is correct.
Answer: (D) Statement I is incorrect but Statement II is correct.
JEE Main · 2022 · 26 Jul 2022 · Shift 1 · Single correct option