JEE Main · 2022 · 25 Jul 2022 · Shift 2 · Equilibrium

In base vs. Acid titration, at the end point methyl orange is present as

(A)quinonoid form✓ Correct
(B)heterocyclic form
(C)phenolic form
(D)benzenoid form

Answer: (A)

Solution

Methyl orange is an azo dye indicator. In acidic solution (at the end point of a base vs. acid titration), it exists in the quinonoid form (red color) due to protonation. In basic solution, it exists in the benzenoid form (yellow color). At the end point of titrating a base with acid, the solution is acidic, so methyl orange is in the quinonoid form. Answer: (A).

JEE Main · 2022 · 25 Jul 2022 · Shift 2 · Single correct option

Practise more: all JEE Main PYQs on Equilibrium →

More JEE Main questions on Equilibrium

The first and second ionization constants of $H_{2} X$ are $2.5 \times 1 0^{- 8}$ and $1.0 \times 1 0^{- 13}$ respectively. The concentration of $X^{2 -}$ in $0.1 M$ $H_{2} X$ solution is $____$ $\times 1 0^{- 15} M$ . (N …
JEE Main 2026View solution →
Which of the following mixture gives a buffer solution with $pH = 9.25$ ?
Given : $pK_{b} (NH_{4} OH) = 4.75$
JEE Main 2026View solution →
Consider the general reaction given below at 400 K
$x A (g) y B (g)$

The values of $K_{p}$ and $K_{c}$ are studied under the same condition of temperature but variation in x and y.
(i) $K_{p} = 85.87$ and $K_{c} = 2.586$ appropriate units
(ii) $K_{p} = 0.862$ and …
JEE Main 2026View solution →
For the following gas phase equilibrium reaction at constant temperature,
$NH X_{3} (g) \frac{1}{2} N X_{2} (g) + \frac{3}{2} H X_{2} (g)$

If the total pressure is $3$ atm and the pressure equilibrium constant ( $K_{p}$ ) is 9 atm, then the degree of dissociation is given as …
JEE Main 2026View solution →
$X_{2} (g) + Y_{2} (g) ⇌ 2 Z (g)$
$X_{2} (g)$ and $Y_{2} (g)$ are added to a 1 L flask and it is found that the system attains the above equilibrium at …
JEE Main 2026View solution →
Consider three metal chlorides $x, y$ and z , where x is water soluble at room temperature, $y$ is sparingly soluble in water at room temperature and z is soluble in hot water. $x, y$ and z are respectively
JEE Main 2026View solution →