In the following reaction
The % yield for reaction I is 60% and that of reaction II is . The overall yield of the complete reaction is __ % [nearest integer]
The % yield for reaction I is 60% and that of reaction II is . The overall yield of the complete reaction is __ % [nearest integer]

Answer: 30
Solution
For consecutive reactions, the overall yield is the product of individual yields.
Starting with n moles of reactant:
Overall yield =
Alternatively, overall yield = 60% × 50% = 0.6 × 0.5 = 0.3 = 30%.
Starting with n moles of reactant:
- After reaction I (60% yield): moles obtained = 0.6n
- After reaction II (50% yield on 0.6n): moles obtained = 0.6n × 0.5 = 0.3n
Overall yield =
Alternatively, overall yield = 60% × 50% = 0.6 × 0.5 = 0.3 = 30%.
JEE Main · 2022 · 27 Jul 2022 · Shift 1 · Integer answer