JEE Main · 2022 · 28 Jul 2022 · Shift 2 · Alcohols Phenols and Ethers

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The major product in the given reaction is
  1. (A)(see structure)
  2. (B)(see structure)
  3. (C)(see structure)
    ✓ Correct
  4. (D)(see structure)

Answer: (C)

Solution

This is an intramolecular free radical bromination reaction. The alkene undergoes addition of HBr in the presence of peroxide (anti-Markovnikov addition). The bromine radical abstracts a hydrogen from the most substituted carbon (tertiary position), and then the resulting radical attacks the double bond intramolecularly to form a five-membered ring. The bromine then adds to the more stable tertiary carbocation position, giving the product shown in option (C).

JEE Main · 2022 · 28 Jul 2022 · Shift 2 · Single correct option

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