A triangular shaped wire carrying 10A current is placed in a uniform magnetic field of 0.5 T , as shown in figure. The magnetic force on segment CD is (Given BC=CD=BD=5cm ).
(A)0.126 N
(B)0.312 N
(C)0.216 N✓ Correct
(D)0.245 N
Answer: (C)
Solution
For a current-carrying segment in a magnetic field, the force is F=BIℓeff, where ℓeff is the effective length perpendicular to the field. Since the triangle is equilateral with side 5 cm, the perpendicular component of CD is 5sin60∘=5×3/2 cm. Thus F=0.5×10×(5×3/2×10−2)=0.5×10×0.0433≈0.216 N.
JEE Main · 2022 · 28 Jul 2022 · Shift 2 · Single correct option