JEE Main · 2023 · 30 Jan 2023 · Shift 2 · Surface Chemistry

The graph of

lo g \frac{X}{m}

lo g p

for an adsorption process is a straight line inclined at an angle of

4 5^{\circ}

with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at the pressure of 0.4 atm is ______

\times 1 0^{- 1}

(Nearest integer)
Given:

lo g 2 = 0.3010

Answer: 16

Solution

The straight line of

lo g \frac{x}{m}

against

lo g p

is the logarithmic form of the Freundlich isotherm,

lo g \frac{x}{m} = lo g k + \frac{1}{n} lo g p .

Its slope is

tan 4 5^{\circ} = 1

, so

\frac{1}{n} = 1

, and its intercept is

lo g k = 0.6020 = lo g 4

, so

k = 4

. At a pressure of

0.4 atm

\frac{x}{m} = k p^{1/ n} = 4 \times 0.4 = 1.6,

which is

16 \times 1 0^{- 1}

JEE Main · 2023 · 30 Jan 2023 · Shift 2 · Integer answer