JEE Main · 2023 · 30 Jan 2023 · Shift 1 · Chemical Bonding and Molecular Structure

Oxygen in $\mathrm{O}{\mathrm{F}}_2$ makes two bonds to fluorine, using four of its six valence electrons and leaving two lone pairs, so the count of two lone pairs holds. With two bond pairs and two lone pairs the electron set is tetrahedral and the molecule is bent, a V-shape rather than linear. Because fluorine is more electronegative than oxygen, oxygen carries the oxidation state $+2$ here, not $-2$. The strong repulsion of the two lone pairs squeezes the F-O-F angle below the $104.5^{\circ }$ of water, to about $103^{\circ }$. The correct statements are that oxygen bears two lone pairs, that the F-O-F angle is less than $104.5^{\circ }$, and that the molecule is bent.