JEE Main · 2023 · 30 Jan 2023 · Shift 1 · Coordination Compounds

Which of the following is correct order of ligand field strength?

(A) $CO < en < NH_{3} < C_{2} O_{4}^{2 -} < S^{2 -}$
(B) $S^{2 -} < C_{2} O_{4}^{2 -} < NH_{3} <$ en $< CO$ ✓ Correct
(C) $NH_{3} <$ en $< CO < S^{2 -} < C_{2} O_{4}^{2 -}$
(D) $S^{2 -} < NH_{3} < en < CO < C_{2} O_{4}^{2 -}$

Answer: (B)

Solution

Ligands are ranked by the splitting they produce in the spectrochemical series. The sulphide ion is a weak-field donor and sits lowest, and the oxalate ion, an oxygen donor, comes next. Ammonia is a stronger nitrogen donor, and ethylenediamine, a chelating diamine, is stronger still than ammonia. Carbon monoxide, a powerful

π

-acceptor, gives the largest splitting of all. The increasing order of field strength is

S^{2 -} < C_{2} O_{4}^{2 -} < N H_{3} < en < CO

JEE Main · 2023 · 30 Jan 2023 · Shift 1 · Single correct option

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JEE Main · 2023 · 30 Jan 2023 · Shift 1 · Coordination Compounds

Solution

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