When 0.01 mol of an organic compound containing $60\%$ carbon was burnt completely, 4.4 g of $\ce{CO2}$ was produced. The molar mass of compound is $\_\_\_\_$ $\mathrm{g~mol}^{-1}$ (Nearest integer)

JEE Main · 2023 · 29 Jan 2023 · Shift 2 · Some Basic Concepts of Chemistry

When 0.01 mol of an organic compound containing

60%

carbon was burnt completely, 4.4 g of

CO X_{2}

was produced. The molar mass of compound is

____

g mol^{- 1}

(Nearest integer)

Answer: 200

The carbon dioxide produced is

4.4

g, which is

\frac{4.4}{44} = 0.1

mol, so the sample contains

0.1

mol of carbon and hence

0.1 \times 12 = 1.2

g of carbon. Since carbon makes up

60%

of the compound by mass, the mass of the sample is

\frac{1.2}{0.60} = 2.0

g, and this corresponds to

0.01

mol of the compound. Its molar mass is therefore

\frac{2.0}{0.01} = 200 g mo l^{- 1}

JEE Main · 2023 · 29 Jan 2023 · Shift 2 · Integer answer