A chloride salt solution acidified with dil. $\mathrm{HNO}_{3}$ gives a curdy white precipitate, [A], on addition of $\mathrm{AgNO}_{3}$. [A] on treatment with $\mathrm{NH}_{4}\mathrm{OH}$ gives a clear solution, B .

(C) $\mathrm{AgCl}$ & $\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]\mathrm{Cl}$

(A) $\mathrm{H}\left[\mathrm{AgCl}_{3}\right]$ & $\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]\mathrm{Cl}$

(B) $\mathrm{H}\left[\mathrm{AgCl}_{3}\right]$ & $\left(\mathrm{NH}_{4}\right)\left[\mathrm{Ag}(\mathrm{OH})_{2}\right]$

(D) $\mathrm{AgCl}$ & $\left(\mathrm{NH}_{4}\right)\left[\mathrm{Ag}(\mathrm{OH})_{2}\right]$

JEE Main · 2023 · 25 Jan 2023 · Shift 2 · Practical and Analytical Chemistry

A chloride salt solution acidified with dil.

HNO_{3}

gives a curdy white precipitate, [A], on addition of

AgNO_{3}

. [A] on treatment with

NH_{4} OH

gives a clear solution, B .

Answer: (C)

The chloride ion of the salt reacts with silver nitrate to throw down the curdy white precipitate of silver chloride,

C l^{-} + AgN O_{3} \to AgCl + N O_{3}^{-}

, so the precipitate is silver chloride. On adding ammonium hydroxide this precipitate dissolves by forming the soluble diamminesilver(I) complex,

AgCl + 2N H_{3} \to [Ag (N H_{3})_{2}] Cl

, giving the clear solution. Thus the precipitate is silver chloride and the clear solution contains diamminesilver(I) chloride.

JEE Main · 2023 · 25 Jan 2023 · Shift 2 · Single correct option