The energy released per fission of nucleus of is 200 MeV. The energy released if all the atoms in 120 g of pure undergo fission is ____ MeV.
(Given )
(Given )
Answer: 6
Solution
The number of atoms in 120 g of the nuclide is . Each fission releases 200 MeV, so the total energy released is MeV. The required number is .
JEE Main · 2023 · 24 Jan 2023 · Shift 2 · Integer answer