A child stands on the edge of the cliff 10 m above the ground and throws a stone horizontally with an initial speed of 5ms−1. Neglecting the air resistance, the speed with which the stone hits the ground will be ____ ms−1 (given, g=10ms−2).
(A)20
(B)15✓ Correct
(C)30
(D)25
Answer: (B)
Solution
The horizontal velocity stays constant throughout the flight, vx=5m s−1. Falling the height h=10m builds a vertical velocity vy=2gh=2(10)(10)=102m s−1. The speed at the ground is the resultant of the two,
v=vx2+vy2=25+200=225=15m s−1.
JEE Main · 2023 · 01 Feb 2023 · Shift 1 · Single correct option