In the given figure the total charge stored in the combination of capacitors is 100 μC. The value of 'x' is ______.
Answer: 5
Solution
The three capacitors are connected across the same 10V, so their charges add: Q=(C1+C2+C3)V=(2+x+3)×10μC. Setting the total equal to 100μC gives (5+x)×10=100, so 5+x=10 and x=5.