In the circuit shown, the energy stored in the capacitor is $n \mu J$. The value of $n$ is ______.

JEE Main · 2023 · 13 Apr 2023 · Shift 2 · Current Electricity

In the circuit shown, the energy stored in the capacitor is

n μ J

. The value of

n

is ______.

Answer: 75

Current in upper branch:

I_{1} = \frac{12}{3 + 9} = 1

A. Current in lower branch:

I_{2} = \frac{12}{4 + 2} = 2

A. Potential difference:

V_{A} - V_{C} = 3 I_{1} = 3

V and

V_{A} - V_{D} = 4 I_{2} = 8

V. Therefore,

V_{C} - V_{D} = 5

V. Energy stored:

U = \frac{1}{2} C V^{2} = \frac{1}{2} \times 6 \times 5^{2} = 75 μ J

. Hence

n = 75

JEE Main · 2023 · 13 Apr 2023 · Shift 2 · Integer answer