JEE Main · 2023 · 13 Apr 2023 · Shift 2 · Capacitance

In the network shown below, the charge accumulated in the capacitor in steady state will be :

(A) $7.2 μ C$ ✓ Correct
(B) $4.8 μ C$
(C) $10.3 μ C$
(D) $12 μ C$

Answer: (A)

Solution

In steady state, no current flows through the capacitor. The circuit reduces to a series combination of the 6 Ω and 4 Ω resistors across the 3 V source. Current

I = \frac{3}{6 + 4} = 0.3

A. Voltage across the 6 Ω resistor (and hence across the capacitor) is

V = 6 \times 0.3 = 1.8

V. Charge on the capacitor:

q = C V = 4 \times 1 0^{- 6} \times 1.8 = 7.2 μ C

JEE Main · 2023 · 13 Apr 2023 · Shift 2 · Single correct option

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