Draw the structural formula of hex-2-en-4-ynoic acid.
Answer: CH₃–C≡C–CH=CH–COOH.
Solution
Six carbons, COOH = C-1; double bond 2–3, triple bond 4–5:
CBSE Class 12 Board · 2006 · Delhi Compartment · Subjective
CBSE Class 12 · 2006 · Delhi Compartment · Aldehydes Ketones and Carboxylic AcidsVery Short Answer
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