Write the IUPAC name of (CH₃)₂C=CH–CO–CH₃.
Answer: 4-Methylpent-3-en-2-one.
Solution
Number from the carbonyl end: C=O at 2, C=C at 3–4, methyl at 4:
CBSE Class 12 Board · 2004 · Delhi · Subjective
CBSE Class 12 · 2004 · Delhi · Aldehydes Ketones and Carboxylic AcidsVery Short Answer
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