Identify and indicate the presence of chirality, if any, in the following molecule. How many stereoisomers are possible for those containing chiral centres? (3-bromopent-1-ene)
Answer: C-3 of CH₂=CH–CHBr–CH₂CH₃ is a chiral centre (four different groups); 2 stereoisomers (a pair of enantiomers).
Solution
3-Bromopent-1-ene: CH=CH–\*CHBr–CH–CH.
C-3 carries four different groups — vinyl (–CH=CH), Br, H and ethyl — so it is a chiral (stereogenic) centre and the molecule is chiral.
One chiral centre ⇒ stereoisomers — the pair of non-superimposable mirror-image enantiomers (d and l).
C-3 carries four different groups — vinyl (–CH=CH), Br, H and ethyl — so it is a chiral (stereogenic) centre and the molecule is chiral.
One chiral centre ⇒ stereoisomers — the pair of non-superimposable mirror-image enantiomers (d and l).
CBSE Class 12 Board · 2004 · Delhi · Subjective