CBSE Class 12 · 2004 · Delhi · Coordination CompoundsShort Answer

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a) Give the IUPAC name of [PtCl(NHCH)(NH)]Cl.
b) Compare the magnetic behaviour of the complex entities [Fe(CN)] and [FeF]. (Atomic number of Fe = 26)

Solution

(a) Ligands alphabetically: ammine, chlorido, methanamine; (−1) + x = +1 ⇒ Pt(II):
\textbf{diamminechlorido(methanamine)platinum(II) chloride}
(b) [Fe(CN)]: Fe = 3d; CN (strong field) pairs all six electrons (t) — no unpaired electron, \textbf{diamagnetic}.
[FeF]: Fe = 3d; F (weak field) leaves all five unpaired — \textbf{paramagnetic},

CBSE Class 12 Board · 2004 · Delhi · Subjective

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