a) Write the formulae of the following complexes:
i) Hexaammineplatinum(IV) chloride
ii) Dichloridotetraamminecobalt(III) ion
b) The dissociation constants of [Cu(NH)] and [Co(NH)] are 1.0 × 10⁻¹² and 6.2 × 10⁻³⁶ respectively. Which complex is more stable and why?
i) Hexaammineplatinum(IV) chloride
ii) Dichloridotetraamminecobalt(III) ion
b) The dissociation constants of [Cu(NH)] and [Co(NH)] are 1.0 × 10⁻¹² and 6.2 × 10⁻³⁶ respectively. Which complex is more stable and why?
Solution
(a)(i)
(ii)
(b) The dissociation constant measures the tendency of the complex to break into its components.
K([Co(NH)]) = 6.2 × 10 ≪ K([Cu(NH)]) = 1.0 × 10.
Hence \textbf{[Co(NH)] is far more stable} — it dissociates to a much smaller extent (its stability constant, 1/K, is larger).
(ii)
(b) The dissociation constant measures the tendency of the complex to break into its components.
K([Co(NH)]) = 6.2 × 10 ≪ K([Cu(NH)]) = 1.0 × 10.
Hence \textbf{[Co(NH)] is far more stable} — it dissociates to a much smaller extent (its stability constant, 1/K, is larger).
CBSE Class 12 Board · 2004 · Delhi Compartment · Subjective