Answer the following:
a) Differentiate between a bidentate ligand and a monodentate ligand.
b) Write the IUPAC name of [Pt(NH)Cl]Cl.
c) Draw the structures of the geometrical isomers of [Co(NH)Cl].
a) Differentiate between a bidentate ligand and a monodentate ligand.
b) Write the IUPAC name of [Pt(NH)Cl]Cl.
c) Draw the structures of the geometrical isomers of [Co(NH)Cl].
Solution
(a) A monodentate ligand coordinates through a single donor atom (HO, NH, Cl); a bidentate ligand holds the metal through two donor atoms simultaneously, forming a chelate ring (ethane-1,2-diamine, oxalate).
(b) 2(−1) + x = +2 ⇒ Pt(IV):
\textbf{tetraamminedichloridoplatinum(IV) chloride}
(c) Octahedral MAB:
\textit{cis} — the two Cl on adjacent corners (90° apart), four NH at the rest;
\textit{trans} — the two Cl on opposite corners (180°), the four NH in the square plane.
(b) 2(−1) + x = +2 ⇒ Pt(IV):
\textbf{tetraamminedichloridoplatinum(IV) chloride}
(c) Octahedral MAB:
\textit{cis} — the two Cl on adjacent corners (90° apart), four NH at the rest;
\textit{trans} — the two Cl on opposite corners (180°), the four NH in the square plane.
CBSE Class 12 Board · 2003 · All India Compartment · Subjective