Write the IUPAC name and draw the structure of the coordination entity of [PtCl(NH)]Cl.
Answer: Pentaamminechloridoplatinum(IV) chloride; octahedral Pt⁴⁺ with five NH₃ and one Cl at the six vertices.
Solution
Charges: (−1) + 0 + x = +3 ⇒ Pt is +4.
Name: \textbf{pentaamminechloridoplatinum(IV) chloride}.
Structure: octahedral — Pt at the centre with the five NH molecules and one Cl occupying the six corners of an octahedron (Cl at one apex, NH at the other five positions); the three Cl counter-ions lie outside the sphere.
Name: \textbf{pentaamminechloridoplatinum(IV) chloride}.
Structure: octahedral — Pt at the centre with the five NH molecules and one Cl occupying the six corners of an octahedron (Cl at one apex, NH at the other five positions); the three Cl counter-ions lie outside the sphere.
CBSE Class 12 Board · 2004 · Delhi · Subjective