CBSE Class 12 · 2003 · Delhi · Coordination CompoundsShort Answer

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Using the valence bond approach, predict the shape and magnetic character of the [Fe(CN)] ion. (Atomic number of Fe = 26)

Answer: Octahedral, d²sp³ (inner orbital); paramagnetic with 1 unpaired electron (low spin).

Solution

Fe oxidation state: x + 6(−1) = −3 ⇒ Fe = 3d.
CN (strong field) pairs the electrons: t — one unpaired electron; two 3d orbitals vacate for dsp.
Shape: octahedral (inner-orbital, low-spin).
Magnetism: 1 unpaired electron → weakly paramagnetic, μ = √3 ≈ 1.73 BM.

CBSE Class 12 Board · 2003 · Delhi · Subjective

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