Using the valence bond approach, deduce the shape and magnetic character of [Co(NH)]. (Atomic number of Co = 27)
Answer: Octahedral, d²sp³ (inner orbital); diamagnetic — all d⁶ electrons paired.
Solution
Co = 3d. NH, a strong-field ligand, forces pairing: t with two 3d orbitals vacated.
Hybridisation: dsp → octahedral, inner-orbital complex.
Magnetic character: zero unpaired electrons → diamagnetic.
Hybridisation: dsp → octahedral, inner-orbital complex.
Magnetic character: zero unpaired electrons → diamagnetic.
CBSE Class 12 Board · 2003 · Delhi · Subjective