CBSE Class 12 · 2002 · All India · Redox Reactions and ElectrochemistryShort Answer

The measured resistance of a conductance cell containing a

7.5 \times 1 0^{- 3}

M solution of KCl at 25°C was 1005 ohms. Calculate (a) the specific conductance and (b) the molar conductance of the solution. (Cell constant = 1.25 cm

^{- 1}

)

Answer: κ ≈ 1.244 × 10⁻³ S cm⁻¹; Λ_m ≈ 165.8 S cm² mol⁻¹

Solution

(a) Specific conductance:

κ = \frac{cell constant}{R} = \frac{1.25}{1005}

κ = 1.244 \times 1 0^{- 3} S c m^{- 1}

(b) Molar conductance:

Λ_{m} = \frac{κ \times 1000}{C} = \frac{1.244 \times 1 0 ^{- 3} \times 1000}{7.5 \times 1 0 ^{- 3}}

Λ_{m} = 165.8 S c m^{2} mo l^{- 1}

CBSE Class 12 Board · 2002 · All India · Subjective

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