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CBSE Class 12 · 2008 · Foreign · Redox Reactions and ElectrochemistryShort Answer

The conductivity of a 0.20 M solution of KCl at 298 K is 0.0248 S cm

^{- 1}

. Calculate its molar conductivity.

Answer: Λ_m = 124 S cm² mol⁻¹

Solution

Λ_{m} = \frac{κ \times 1000}{C} = \frac{0.0248 \times 1000}{0.20}

Λ_{m} = 124 S c m^{2} mo l^{- 1}

CBSE Class 12 Board · 2008 · Foreign · Subjective

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