Using matrices, solve the following system of equations:2x+3y+3z=5,x−2y+z=−4,3x−y−2z=−3.Answer: x=−207, y=2037, z=201 \,SolutionForm AX=B with A=2133−2−131−2, B=5−4−3; ∣A∣=0, so X=A−1B. Solving the system yieldsx=−207, y=2037, z=201.x=−207, y=2037, z=201CBSE Class 12 Board · 2007 · Subjective