Using matrices, solve the following system of equations:x+y+z=3,x−2y+3z=2,2x−y+z=2.Answer: x=1, y=1, z=1SolutionWith A=1121−2−1131, B=322, we have ∣A∣=0, so X=A−1B.Solving gives x=1, y=1, z=1 (check: 1+1+1=3, 1−2+3=2, 2−1+1=2).x=1, y=1, z=1CBSE Class 12 Board · 2006 · Subjective