Solve the following differential equation: dxdy+2ytanx=sinxAnswer: ysec2x=secx+C (i.e. y=cosx+Ccos2x)SolutionLinear with P=2tanx.I.F.=e∫2tanxdx=e2log∣secx∣=sec2xysec2x=∫sinxsec2xdx=∫secxtanxdx=secx+Cysec2x=secx+C ⇒ y=cosx+Ccos2xCBSE Class 12 Board · 2006 · Subjective