Evaluate ∫02(x2+2x+1)dx as limit of a sums.Answer: 326Solutionf(x)=x2+2x+1=(x+1)2, a=0,b=2,h=n2,nh=2, with f(rh)=r2h2+2rh+1.∫02f(x)dx=h→0limhr=0∑n−1(r2h2+2rh+1)=h→0lim[h36(n−1)n(2n−1)+2h22(n−1)n+nh]As n→∞ with nh=2:=3(nh)3+(nh)2+nh=38+4+2=326CBSE Class 12 Board · 2007 · Subjective