If x=asin2t(1+cos2t) and y=bcos2t(1−cos2t), show that (dxdy)t=π/4=ab.Answer: ab (proved)SolutionExpand and use double-angle forms. For x:x=asin2t+2asin4t ⇒ dtdx=2acos2t+2acos4tFor y (with cos22t=21+cos4t):y=bcos2t−2b−2bcos4t ⇒ dtdy=−2bsin2t+2bsin4tHence:dxdy=2a(cos4t+cos2t)2b(sin4t−sin2t)=a(cos4t+cos2t)b(sin4t−sin2t)At t=4π: sin4t=sinπ=0, sin2t=sin2π=1, cos4t=cosπ=−1, cos2t=cos2π=0:dxdy=a(−1+0)b(0−1)=ab(dxdy)t=π/4=abCBSE Class 12 Board · Subjective